2[w-(3w+19)+16]=2(w+3)

Solution for 2[w-(3w+19)+16]=2(w+3) equation:

Simplifying
2[w + -1(3w + 19) + 16] = 2(w + 3)

Reorder the terms:
2[w + -1(19 + 3w) + 16] = 2(w + 3)
2[w + (19 * -1 + 3w * -1) + 16] = 2(w + 3)
2[w + (-19 + -3w) + 16] = 2(w + 3)

Reorder the terms:
2[-19 + 16 + w + -3w] = 2(w + 3)

Combine like terms: -19 + 16 = -3
2[-3 + w + -3w] = 2(w + 3)

Combine like terms: w + -3w = -2w
2[-3 + -2w] = 2(w + 3)
[-3 * 2 + -2w * 2] = 2(w + 3)
[-6 + -4w] = 2(w + 3)

Reorder the terms:
-6 + -4w = 2(3 + w)
-6 + -4w = (3 * 2 + w * 2)
-6 + -4w = (6 + 2w)

Solving
-6 + -4w = 6 + 2w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-2w' to each side of the equation.
-6 + -4w + -2w = 6 + 2w + -2w

Combine like terms: -4w + -2w = -6w
-6 + -6w = 6 + 2w + -2w

Combine like terms: 2w + -2w = 0
-6 + -6w = 6 + 0
-6 + -6w = 6

Add '6' to each side of the equation.
-6 + 6 + -6w = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -6w = 6 + 6
-6w = 6 + 6

Combine like terms: 6 + 6 = 12
-6w = 12

Divide each side by '-6'.
w = -2

Simplifying
w = -2